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I thought “residual current circuit breaker” was just the European name for what we call a GFCI in the US.

Besides the overexposure bias, I also found the A33′s metering system was prone to more variation than I’m accustomed to seeing in an SLR. The few times I had it locked down on a tripod, shot to shot exposure seemed pretty consistent, but on several occasions shooting handheld, I found significant variation between successive shots, apparently resulting from fairly minor changes in framing. I’d of course expect exposure to vary to follow changes in the scene, but the amount of variation I saw between very similar shots taken with the A33 was unusual.

Just curious, what size pump do you have? The Sonoff claims 10A per channel, but my 1HP pump needs a 40-50A relay to safely deal with cold-start current. Unless the relays are overspec’d I’d be worried about literally burning out those contacts pretty fast.

I’d like to say that if a circuit breaker is X-degrees over ambient, it’s a problem… but there’s just no hard and fast rule for this. I can’t say this.

Take a look at the Lennox air conditioning condensing unit tag on Page 19. Notice that the MCA is 28.6 amps and the maximum fuse or circuit breaker is 50 amps. This means it is allowable to install this unit on a circuit breaker rated at 50 amps and a conductor rated at 28.6 amps, according to the NEC’s NFPA 70.

And because what you need is power and not current, and because of voltage drop in your wiring, the current is slightly more than twice. If you have a load of 1200 Watts, so 10 A in 120VAC and 5 A in 240 VAC. With wire around 8 ohms/km (roughly wire of 2.5mm² section or 14 AWG), you get a voltage drop of 8 Volts in one case, 4 Volts in the other. So 6.67% of your main voltage vs. 1.67% of your main voltage. Already 5% of efficiency loss in your system… But it’s even worst because in this case you don’t get 1200 Watts at your load, only 1120 Watts ((120-8) * 10) and 1180 Watts ((240-4) * 5) To get your 1200 Watts at your charge, you need 10.77 Amps and 5.08 Amps. So you get a overall efficiency of 92.8 % at 120 VAC (1200 / (10.77*120)) and 98.3 % at 240 VAC. (5.5% of efficiency difference).

I’ve not tried to account for phase differences (that is, power factor). It’s very naive. I measure the current via a CT and compute RMS across a whole cycle, then I find the peak voltage and do the math.

There are people that play with high voltage stuff like Tesla coils, induction heaters etc. Now those know enough to respect high voltage.

The spark-gap Tesla coil itself was

Senate Majority Leader Mitch McConnell has been clear that, aside from any spending bills, Republicans’ priority for the end of the year is to keep pushing judges through — and if Flake holds on this issue, it could throw a wrench into that plan.

Waterjet, who seemingly has no concept of how a basic opto-isolated diac-driven triac circuit works, chimes in with useless blabber about insufficient current ratings of the *optoisolator* — seriously? If you’re going to throw stones at someone, perhaps you could verify that you have somewhat of a clue of what you’re talking about?

The ESD protective wrist strap should not tie you to a hard ground, it usually has a 1Meg resistor included, just for this reason. But perhaps not every cheap chinese one has?